Multiple Capture Card Question on GB-PVR v 1.29

[TimCoe]

I am still somewhat of a novice on GB-PVR. I recently built a new machine and in the process decided to have two capture cards. The original card was a PVR-150. The new card is a HVR-1600. I thought I understood the documentation in that each card required a different board number.

Take notice to Board Number item:

http://gbpvr.com/pmwiki/pmwiki.php/Config/DefineSource

When I assigned board 1 to the pvr-150 all worked OK. I added the hvr-1600 as board 2. When I tried to configure it GB-PVR reported that the drivers appeared to not be installed. If I continued with the configuration it would allow me to but it would not record. It allowed me to schedule but would not record. I used the devchecker utility and it only showed one card installed ; the pvr-150. So I uninstalled both cards and started again… Same thing. Just for fun I made both cards board #1. It allowed me to configure both cards. It works flawless and allows us to record two shows simultaneously. My wife loves it…. now she can record American Idol and Dancing with the Stars. Life is good... for her!

So I am confused. Why does it work with both cards defined as board 1? Is it because the pvr-150 and the hvr-1600 are similar? I thought I read somewhere that the hvr-1600 was the replacement for the pvr-150.

Thanks in advance.

[gEd]

Board Number
If you have two or more of the same card, you will have to differenciate between the cards here. But you can’t just select different numbers. Your computer already knows the number it wants you to use. Follow these instructions to find out what numbers your computer are using.

i.e. if you had 2 x pvr-150's you would set them up as board #1 and #2 but as you have 2 different tuners, they should both be set as #1, as you have now found out.

[TimCoe]

Ok, Thanks for the reply. sorry for being dense. The fact that the cards are different means they are both #1 as opposed to having 2 pvr-150's or 2 hvr1600's which would mean each card has it's own unique number. I think I got it now.